//Mu地图解密函数 EncTerrainX.att->TerrainX.att
int DecodeATT(unsigned char *OutData,const unsigned char *InData, int Len, int Type)
{
//Type为1是韩版新格式。返回长度都是65536
unsigned char XorData[]={0xD1,0x73,0x52,0xF6,0xD2,0x9A,0xCB,0x27,0x3E,0xAF,0x59,0x31,0x37,0xB3,0xE7,0xA2};
unsigned char cl=0x5E;
unsigned char tmp1[65540],tmp2[131076],tmpData1[65540],tmpData2[131076];
int i,j;
if (Type!=1)
{
if (Len!=65540) return -1;
for(i=0;i<Len;i++)
{
j=i;
tmp1[i]=(InData[i]^XorData[j])-cl;
cl=InData[i]+0x3D;
}
XorFCCFAB(tmpData1,tmp1,Len);
memcpy(OutData,&tmpData1[4],65536);
return 0;
}
else
{
if (Len!=131076) return -1;
for(i=0;i<Len;i++)
{
j=i;
tmp2[i]=(InData[i]^XorData[j])-cl;
cl=InData[i]+0x3D;
}
XorFCCFAB(tmpData2,tmp2,Len);
for(i=0;i<65536;i++)
{
OutData[i]=tmpData2[(i*2)+4];
}
return 0;
}
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